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UPSC Recruitment 2019 12 Livestock Officer

Union Public Service Commission

UPSC Recruitment 2019 – UPSC invites Online applications for recruitment of 12 Medical Officer/Research Officer (Siddha), Ministry of AYUSH, Assistant Director, Central Poultry, Livestock Officer, Assistant Legal Adviser, Deputy Fire Adviser Posts. UPSC Recruitment 2019 12 Livestock Officer Posts This online facility will be available in the Official website www.upsc.gov.in from 23.08.2019 to 12.09.2019.

UPSC Recruitment 2019 12 Livestock Officer Assistant Director, Central Poultry, Assistant Legal Adviser Posts

UPSC Recruitment 2019 12 Livestock Officer

Highlights for UPSC Recruitment 2019 12 Livestock Officer Posts:

Organization Name: Union Public Service Commission

Official website: www.upsc.gov.in

Job Category: Central Govt Jobs

Job Role: Medical Officer, Assistant Director, Central Poultry, Livestock Officer

Total No of Vacancies: 12

Qualification: Degree in Siddha/Veterinary Science, LLB, Master’s Degree in law, Fire Engineering

Age Limit: 35 – 40 Years

Job Location: All Over India

Salary Details: Level-7 to Level-11 in the Pay Matrix CPC

Selection Procedure: Written Exam, Interview

Application Fee/Exam Fee: Rs. 25/-

Last date: 12.09.2019

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How to apply online for UPSC Livestock Officer Post:

  • Eligible candidates can apply online through the Official website www.upsc.gov.in from 23.08.2019 to 12.09.2019. Before applying, Candidates should ensure that they fulfill the eligibility criteria as per published in the online advertisement.

Important date:

  • Starting Date for Submission of Application: 23.08.2019
  • Last date for Submission of Application: 12.09.2019

Important Links:

UPSC Official Website Career Page
UPSC Official Notification PDF
UPSC Online Application Form

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